![An elementary course of infinitesimal calculus . t—y 19] CONTINUITY. 43 Since sinh x and cosh x are continuous, whilst cosh xnever vanishes, it follows that tauha; is continuous for allvalues An elementary course of infinitesimal calculus . t—y 19] CONTINUITY. 43 Since sinh x and cosh x are continuous, whilst cosh xnever vanishes, it follows that tauha; is continuous for allvalues](https://c8.alamy.com/comp/2CDC7EA/an-elementary-course-of-infinitesimal-calculus-ty-19-continuity-43-since-sinh-x-and-cosh-x-are-continuous-whilst-cosh-xnever-vanishes-it-follows-that-tauha-is-continuous-for-allvalues-of-x-fig-22-shews-the-curve-y-=-tanh-xthis-has-the-lines-y-=-1-as-asymptotes-it-is-evident-from-the-definitions-1-that-cosh-sinh-a-=-e-cosh-x-sinh-x-=-e-3whence-by-multiplication-cosh-x-sinh-x-=-4-from-this-we-derive-dividing-by-cosh-a-and-sinh-arespectively-sech-x=-tanh-a-1-cosech-a-=-coth-a-1-the-forraulse-4-and-5-corresponcl-to-the-trisjo-2CDC7EA.jpg)
An elementary course of infinitesimal calculus . t—y 19] CONTINUITY. 43 Since sinh x and cosh x are continuous, whilst cosh xnever vanishes, it follows that tauha; is continuous for allvalues
![SOLVED: 6 . Let x = tanh T1 y be the inverse function of y = tanh . Show that 51 1+V y3 y5 tanh y = log =y + + + SOLVED: 6 . Let x = tanh T1 y be the inverse function of y = tanh . Show that 51 1+V y3 y5 tanh y = log =y + + +](https://cdn.numerade.com/ask_images/ed9d7800bd7b4c67bebf37930e697292.jpg)
SOLVED: 6 . Let x = tanh T1 y be the inverse function of y = tanh . Show that 51 1+V y3 y5 tanh y = log =y + + +
![Activation curve for hyperbolic tangent function used in simulations: y... | Download Scientific Diagram Activation curve for hyperbolic tangent function used in simulations: y... | Download Scientific Diagram](https://www.researchgate.net/publication/2439950/figure/fig2/AS:670715456012296@1536922434260/Activation-curve-for-hyperbolic-tangent-function-used-in-simulations-y-tanh-x-2.png)